Factor label question. finding thickness given length, weight, and density of a piece of aluminum fo

a piece of aluminum foil measuring 12.0 in by 15.5 in has a mass of 0.18 ounces. find the thickness of the foil in millimeters given that the aluminum has a density of 2.70 g/cm^3.

*we are required to complete the problem all in a row with only ONE equals sign at the end.

im starting out with ounces, and once i get to cubic inches i am not sure how to plug in the length and the width into the problem without stopping and starting again.

1 in^3 I ?????????? I ....

2.54^3 cm^3 I 12.0 in x 15.5 in I ....

i am pretty sure that what i did was valid, but i dont know how to do that in the proper format. i came up with 0.15 mm, which seems reasonable, but i need to know what is the correct way to set up this problem. i understand the concept of this, so i am just asking for a step by step explaination( ie, go from ounces to grams, from grams to cm^3 etc.), an explanation of the above ?????, and a confirmation of the answer.

thank you

Factor label question. finding thickness given length, weight, and density of a piece of aluminum foil.?

28.34952 grams = 1 oz.

So find out how many grams of aluminum you have:

0.18 oz * 28.34 grams/ oz = 5.103 grams Al

Most people think of aluminum as 2D but really, it is a rectangular prism, and the volume of any rectangular prism is

Base * Height * width = Volume.

Since you know the density of the material, and you know the mass however, you can calculate volume that way also.

5.103 grams/2.70g/cm^3 = 1.89 cm^3

Also convert all dimensions into metric system, since that is what the problem is asking for.

So 1 in = 25.4 mm.

1 cm^3 = 1000mm^3

so 1.89 cm^3 = 1890 mm^3

So now we have Base * Height * width = 1890mm^3

We are solving for width, so width = 1890 cm^3 / (base*height)

width = 1890/(12*25.4*15.5*25.4)

width = 0.01575 mm

Your answer was off by a power of 10.

Hope this helps.

Factor label question. finding thickness given length, weight, and density of a piece of aluminum foil.?uninstall internet explorer internet explorer

0.18 oz *(1 lb/16 oz)*(454 g/lb)*(1 cm^3 / 2.70 g)*(10 mm/1 cm)^3 / [(12 in*2.54 cm/in*10mm/cm)*(15.5 in*2.54 cm/in*10 mm/cm)]

I converted the oz to grams, then grams to cubic cm, which I then divided by the product of the length and width in cm. That should end up with the thickness in mm, all in one line.

Someone check my work pleez.